[VAC] Re: Elect. portion of Frig.

["Richard P. Kenan" <as5368@xxxxxxxxxxxxxx>]

If the *only* thing in the circuit is the heating element, then that's 
correct - you would be connected directly across the source voltage, and 
would see that reading on the meter, regardless of the condition of the 
heating element.  If there were other resistances in the circuit, then the 
drop across a good element would be lower than line voltage, and that 
across a bad element would be near line voltage on an analog voltmeter.

- Dick
(5368)